Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Explore thousands of questions and answers from a knowledgeable community of experts ready to help you find solutions. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
Answer: the drawdown of the lake in centimeters is 3.02 cm
Explanation:
Given data;
Power of motor = 1000 W
efficiency M = 50% = 0.5
so Effective power = 1000 × 0.5 = 500 W
time t = 2 hrs = 2 × 60 × 60 = 7200 secs
so
Energy = p × t = 500 × 7200 = 3,600,000 J
Now Energy required to pump water to height h = mgh (J)
3,600,000 J = mgh
m = 3,600,000 / gh
given that; h is 2.43 and we know that g is 9.81, we substitute
m = 3,600,000 / (9.81 × 2.43)
m = 3,600,000 / 23.8383
m = 151017.48 kg
Now we know that, Volume = Mass / Density      [density of water]
so, Volume = 151017.48 Â / 1000
Volume = 151.01748 kg/m³
given that surface area = 5000 m²
Drawdown = 151.01748 / 5000
Drawdown = 0.3020 m
we convert to centimeter
Drawdown = 0.3020 m × 100
Drawdown = 3.02 cm
Therefore the drawdown of the lake in centimeters is 3.02 cm
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.