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Sagot :
Answer:
[tex]V_a =1.4285m/s[/tex]
Explanation:
From the question we are told that
70 kg astronaut
5 kg ball
A velocity of 20 m/s east
Generally with Law of conservation of momentum in place for a body in space
initial and final momentum must be equal
Therefore
[tex]M_b*V_b=M_a*V_a[/tex]
[tex]M_b=Mass of ball \\V_b=Ball velocity \\M_a= Mass of astronaut \\V_a= Astronaut velocity[/tex]
Mathematically solving for[tex]V_a[/tex]
[tex]V_a =\frac{5*20}{70}[/tex]
[tex]V_a =1.4285m/s[/tex]
Therefore the Astronauts velocity relative to his mass is given to be
[tex]V_a =1.4285m/s[/tex]
The velocity of the astronaut is 1.43 m/s.
From Newton's third law of motion,
To get the velocity of the astronaut, we use the formula below.
Formula:
- MV = mv.................... Equation 1
Where:
- M = mass of the astronaut
- V = Velocity of the astronaut
- m = mass of the ball
- v = velocity of the ball.
make V the subject of the equation
- V = mv/M................. Equation 2
From the question,
Given:
- m = 5 kg
- v = 20 m/s
- M = 70 kg
Substitute these values into equation 2.
- V = 5(20)/70
- V = 1.43 m/s.
Hence, the velocity of the astronaut is 1.43 m/s.
Learn more about velocity here: https://brainly.com/question/6504879
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