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Sagot :
Answer:
a) 0.118.
Explanation:
The computation of the UCL is shown below:
Given that
N = 100
Sample Sample size Number of retests fraction defective
1 100 4 0.04
2 100 11 0.11
3 100 6 0.06
4 100 10 0.1
5 100 4 0.04
6 100 6 0.04
7 100 1 0.01
8 100 6 0.06
9 100 9 0.09
10 100 11 0.11
Total 1,000 68
Now p is
= 68 ÷ 1000
= 0.068
Now the standard deviation is
= √p(1 - p) ÷ √n
= √0.068 × (1 - 0.068) ÷ √100
= 0.025
Now the UCL is
= p + z × standard deviation
= 0.068 + 2 × 0.025
= 0.118
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