Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
Answer:8.0 m/s^2
Explanation: The ball is traveling in uniform circular motion at the speed of 2 m/s in a path of the radius that is 0.50 meters.
v^2/r
2.0 m/s^2/ 0.50 m= 8.0 m/s^2
The magnitude of the ball's centripetal acceleration is [tex]\rm 8 \;m/sec^2[/tex] and this can be determined by using the formula of the centripetal acceleration.
Given :
A ball attached to a string is whirled at a constant speed of 2.0 meters per second in a horizontal circle of a radius of 0.50 meters.
The following steps can be used in order to determine the magnitude of the ball's centripetal acceleration:
Step 1 - The formula of the centripetal acceleration can be used in order to determine the magnitude of the ball's centripetal acceleration.
Step 2 - The formula of the centripetal acceleration is given below:
[tex]\rm a_c=\dfrac{v^2}{r}[/tex]
Step 3 - Substitute the values of the known terms in the above formula.
[tex]\rm a_c=\dfrac{2^2}{0.5}[/tex]
Step 4 - Simplify the above expression.
[tex]\rm a_c = 8\;m/sec^2[/tex]
For more information, refer to the link given below:
https://brainly.com/question/17689540
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.
