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Sagot :
Answer:8.0 m/s^2
Explanation: The ball is traveling in uniform circular motion at the speed of 2 m/s in a path of the radius that is 0.50 meters.
v^2/r
2.0 m/s^2/ 0.50 m= 8.0 m/s^2
The magnitude of the ball's centripetal acceleration is [tex]\rm 8 \;m/sec^2[/tex] and this can be determined by using the formula of the centripetal acceleration.
Given :
A ball attached to a string is whirled at a constant speed of 2.0 meters per second in a horizontal circle of a radius of 0.50 meters.
The following steps can be used in order to determine the magnitude of the ball's centripetal acceleration:
Step 1 - The formula of the centripetal acceleration can be used in order to determine the magnitude of the ball's centripetal acceleration.
Step 2 - The formula of the centripetal acceleration is given below:
[tex]\rm a_c=\dfrac{v^2}{r}[/tex]
Step 3 - Substitute the values of the known terms in the above formula.
[tex]\rm a_c=\dfrac{2^2}{0.5}[/tex]
Step 4 - Simplify the above expression.
[tex]\rm a_c = 8\;m/sec^2[/tex]
For more information, refer to the link given below:
https://brainly.com/question/17689540
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