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Sagot :
Answer:
The amount of kinetic energy lost during the collision is 60.75 J
Explanation:
The given parameters are;
The mass of the object moving in the +x direction, m₁ = 1.00 kg
The velocity of the object moving in the +x direction, v₁ = 10.0 m/s
The mass of the object moving in the -x direction, m₂ = 1.50 kg
The velocity of the object moving in the +x direction, v₂ = 5.00 m/s
The final velocity of the 1.00 kg mass after collision, v₃ = 4.00 m/s
The direction of motion of the 1.00 kg mass after collision = -x direction
The total initial kinetic energy of the system, [tex]K.E._{total \ initial}[/tex] = 1/2·m₁·v₁² + 1/2·m₂·v₂²
∴ [tex]K.E._{total \ initial}[/tex] = 1/2×1.00×10² + 1/2×1.50×5² = 68.75 J
The final kinetic energy of the system, [tex]K.E._{final}[/tex] = 1/2·m₁·v₃²
[tex]K.E._{final}[/tex] = 1/2×1.00×4² = 8 J
The amount of kinetic energy lost during the collision, [tex]\Delta K.E._{system}[/tex] is given as follows;
[tex]\Delta K.E._{system}[/tex] = [tex]K.E._{final}[/tex] -[tex]K.E._{total \ initial}[/tex] = 8 J - 68.75 J = -60.75 J
The amount of kinetic energy lost during the collision = 60.75 J.
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