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An oatmeal container has a diameter of 9 inches and a volume of 239.4 in3. What is the lateral surface area of the oatmeal container? Hint: You have to use the Volume to find the height before you can calculate the lateral surface area. Round your answer to the nearest tenth.

Sagot :

Answer:

Lateral surface area = 106.4 [tex]in^{2}[/tex].

Step-by-step explanation:

Assumed that the oatmeal container has the shape of a cylinder. Its lateral surface area can be determined by:

lateral surface area = 2[tex]\pi[/tex]rh

But,

volume = [tex]\pi[/tex][tex]r^{2}[/tex]h

where: r is the radius, and h is the height.

From the question, volume = 239.4 [tex]in^{3}[/tex], and diameter = 9 inches, then;

radius = [tex]\frac{diameter}{2}[/tex] = [tex]\frac{9}{2}[/tex]

          = 4.5

radius = 4.5 inches

Thus,

volume = [tex]\pi[/tex][tex]r^{2}[/tex]h

239.4 = [tex]\pi[/tex]x [tex](4.5)^{2}[/tex] x h

          = 20.25[tex]\pi[/tex]h

h = [tex]\frac{239.4}{20.25\pi }[/tex]

  = [tex]\frac{11.8222}{\pi }[/tex]

h = [tex]\frac{11.8222}{\pi }[/tex] inches

Therefore,

lateral surface area = 2[tex]\pi[/tex]rh

                                = 2[tex]\pi[/tex](4.5)([tex]\frac{11.8222}{\pi }[/tex])

                                = 2 x 4.5 x 11.8222

                                = 106.3998

Lateral surface area of the oatmeal container is 106.4 [tex]in^{2}[/tex].

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