Answer:
6.64 seconds
Step-by-step explanation:
Given that:
Distance between roof of the terminal and ground = 709 feet
A bucket was dropped from the roof.
To find:
The time taken by the bucket to hit the ground?
Solution:
Distance traveled, [tex]s[/tex] = 709 feet
Initial velocity of the bucket, [tex]u[/tex] = 0 feet/sec (because initially it was at rest)
Acceleration of the bucket will be equal to acceleration due to gravity i.e.
[tex]g[/tex] or 32.1741 [tex]ft/sec^{2}[/tex]
Let the time taken is [tex]t[/tex] seconds.
Formula for distance is given as:
[tex]s = ut+\dfrac{1}{2}at^2[/tex]
Putting all the values:
[tex]709 = 0 (t) + \dfrac{1}{2}(32.1741) t^2\\\Rightarrow 1418 = 32.1741 t^2\\\Rightarrow t^2 = 44.07\\\Rightarrow t \approx \bold{6.64\ sec}[/tex]
