Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
Answer:
0.7 moles of Ag are produced
Explanation:
Given data:
Mass of silver carbonate = 97.4 g
Moles of silver produced = ?
Solution:
Chemical equation:
2Ag₂CO₃ → 4Ag + 3CO₂
Number of moles of Ag₂CO₃ :
Number of moles = mass/molar mass
Number of moles = 97.4 g/ 275.75 g/mol
Number of moles = 0.35 mol
Now we will compare the moles of Ag and Ag₂CO₃.
Ag₂CO₃ : Ag
2 : 4
0.35 : 4/2×0.35 = 0.7
0.7 moles of Ag are produced.
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.