Answered

Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

A 200 gram mass is placed on the meter stick 20 cm from the pivot point (the fulcrum). An unknown mass is positioned 8 cm from the fulcrum to balance the system. What is the mass of this unknown object?

Sagot :

heckheck4

Answer:

80 grams

Explanation:

multiplying 8 by 2.5 to get 20

so then deviding 200 by that 2.5 will get you 80 grams

hamzaahmeds

This question involves the concepts of equlibrium and moment.

The mass of unknown object should be "500 g".

EQUILIBRIUM

In order to balance the meter stick equilibrium should be achieved. For equilibrium the moment due to each mass must be the same.

[tex]F_1d_1=F_2d_2\\m_1gd_1=m_2gd_2\\m_1d_1=m_2d_2[/tex]

where,

  • m₁ = mass of known object = 200 g
  • m₂ = mass of unknown object = ?
  • d₁ = distance from fulcrum of known object = 20 cm
  • d₂ = distance from fulcrum of unknown object = 8 cm

Therefore,

[tex](200\ g)(20\ cm)=(m_2)(8\ cm)\\\\m_2=\frac{(200\ g)(20\ cm)}{8\ cm}[/tex]

m₂ = 500 g

Learn more about moment here:

https://brainly.com/question/6278006

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.