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Find the distance between the two points rounding to the nearest tenth (if necessary).
(-4, 2) and (2,-6)

Sagot :

Space

Answer:

[tex]\displaystyle d = 10[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Algebra II

  • Distance Formula: [tex]\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Explanation:

Step 1: Define

Point (-4, 2)

Point (2, -6)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

  1. Substitute [DF]:                              [tex]\displaystyle d = \sqrt{(2+4)^2+(-6-2)^2}[/tex]
  2. (Parenthesis) Add/Subtract:          [tex]\displaystyle d = \sqrt{(6)^2+(-8)^2}[/tex]
  3. [√Radical] Exponents:                   [tex]\displaystyle d = \sqrt{36+64}[/tex]
  4. [√Radical] Add:                              [tex]\displaystyle d = \sqrt{100}[/tex]
  5. [√Radical] Evaluate:                      [tex]\displaystyle d = 10[/tex]
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