Answer:
The change in the object's velocity is 6.25 m/s
Explanation:
Force
According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:
F = ma [1]
Where a is the acceleration of the object.
On the other hand, the equations of the Kinematics describe the motion of the object by the equation:
[tex]v_f=v_o+at\qquad\qquad[2][/tex]
Where:
vf is the final speed
vo is the initial speed
a is the acceleration
t is the time
It's given a constant force of F=4.5 N acts on an object of mass m=7.2 kg. The object has an acceleration we can calculate solving [1] for a:
[tex]a=\frac{F}{m}[/tex]
[tex]a=\frac{4.5}{7.2}=0.625[/tex]
[tex]a=0.625\ m/s^2[/tex]
It's required con compute the change of velocity (or its magnitude, the speed). From [2]:
[tex]v_f-v_o=at[/tex]
The expression at the left side is the change of speed Δv:
[tex]\Delta v=at[/tex]
Knowing the time is t=10 s:
[tex]\Delta v=0.625*10[/tex]
[tex]\Delta v=6.25\ m/s[/tex]
The change in the object's velocity is 6.25 m/s
