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Solve the equation x^2-6x-1=0 to the nearest tenth.

Sagot :

sqdancefan

9514 1404 393

Answer:

  x = {-0.2, 6.2}

Step-by-step explanation:

The values that go into the quadratic formula are a = 1, b = -6, c = -1.

  [tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-(-6)\pm\sqrt{(-6)^2-4(1)(-1)}}{2(1)}\\\\=\dfrac{6\pm\sqrt{40}}{2}=3\pm\sqrt{10}\\\\\boxed{x\in\{-0.2,\ 6.2\}}[/tex]

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