Answered

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URGENT
A force of 35 N is used to stretch a spring 15 cm beyond its normal length. What is the
increase in the spring's energy?

Sagot :

machmillerg

Answer:

5.25 J

Explanation:

W = PE = (f)(x)

PE = 35N*0.15m

PE = 5.25 N*m

1 N*m = 1 J

PE = 5.25 J

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