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Given \qquad m \angle QPS = 107^\circm∠QPS=107 ∘ m, angle, Q, P, S, equals, 107, degrees \qquad m \angle RPS = 4x + 27^\circm∠RPS=4x+27 ∘ m, angle, R, P, S, equals, 4, x, plus, 27, degrees \qquad m \angle QPR = 9x - 115^\circm∠QPR=9x−115 ∘ m, angle, Q, P, R, equals, 9, x, minus, 115, degrees Find m\angle QPRm∠QPRm, angle, Q, P, R:

Sagot :

Answer:

20°

Step-by-step explanation:

4x+27°+9x-115°=107°

4x+9x + 27°-115°=107°

13x-88°=107°

add 88 on both sides

13x=195°

divide 13 on both sides

x=15

9(15°)-115°

135°-115° = 20

The answer is 20

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