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Sagot :
Answer:
4) yes, the rate is 3
5) no
6) yes, the rate is 5
Step-by-step explanation:
Direct variation is y = kx.
4.
First, substitute your values into the equation for direct variation to find K, the rate.
3 = k(1)
3 = k
Now let's see if this holds true.
6 = 3(2)
6 = 6
This looks true, but let's do another one from the table.
9 = 3(3)
9 = 9
And another just to check.
12 = 3(4)
12 = 12
So, #4 is direct variation.
5.
1 = k(2)
1/2 = k
Let's test for all of the other values to be sure.
2 = (1/2)(3)
2 ≠ 1.5
3 = (1/2)(4)
3 ≠ 2
This is not true. #5 is not an example of direct variation.
6.
5 = k(1)
5 = k
Time to check.
10 = 5(2)
10 = 10
Again.
15 = 5(3)
15 = 15
Again.
20 = 5(4)
20 = 20
One last time...
25 = 5(5)
25 = 25
#6 is an example of direct variation.
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