Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Get quick and reliable solutions to your questions from a community of seasoned experts on our user-friendly platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

Surface Area of a can is 517.8 cm^2. Maximize the volume of this can using the measured surface area.

Sagot :

Answer:

[tex]r = 5.24[/tex] --- Radius

[tex]h = 10.48[/tex] --- Height

Explanation:

Given

Object: Can (Cylinder)

[tex]Surface\ Area = 517.8cm^2[/tex]

Required

Maximize the volume

The surface area is:

[tex]S.A = 2\pi r^2 + 2\pi rh[/tex]

Substitute 517.8 for S.A

[tex]517.8 = 2\pi r^2 + 2\pi rh[/tex]

Divide through by 2

[tex]258.9 = \pi r^2 + \pi rh[/tex]

Factorize:

[tex]258.9 = \pi r(r + h)[/tex]

Divide through by [tex]\pi r[/tex]

[tex]\frac{258.9}{\pi r} = r + h[/tex]

Make h the subject

[tex]h = \frac{258.9}{\pi r} - r[/tex] --- (1)

Volume (V) is calculated as:

[tex]V = \pi r^2h[/tex]

Substitute (1) for h

[tex]V = \pi r^2(\frac{258.9}{\pi r} - r)[/tex]

Open Bracket

[tex]V = 258.9r - \pi r^3[/tex]

Differentiate V

[tex]V' = 258.9 - 3\pi r^2[/tex]

Set V' to 0

[tex]0 = 258.9 - 3\pi r^2[/tex]

Collect Like Terms

[tex]3\pi r^2 = 258.9[/tex]

Divide through by 3

[tex]\pi r^2 = 86.3[/tex]

Divide through by [tex]\pi[/tex]

[tex]r^2 = \frac{86.3}{\pi}[/tex]

[tex]r^2 = \frac{86.3*7}{22}[/tex]

[tex]r^2 = \frac{604.1}{22}[/tex]

Take square root of both sides

[tex]r = \sqrt{\frac{604.1}{22}[/tex]

[tex]r = 5.24[/tex]

Recall that:

[tex]h = \frac{258.9}{\pi r} - r[/tex]

Substitute 5.24 for r

[tex]h = \frac{258.9}{\pi * 5.24} - 5.24[/tex]

[tex]h = \frac{258.9*7}{22 * 5.24} - 5.24[/tex]

[tex]h = \frac{1812.3}{115.28} - 5.24[/tex]

[tex]h = 15.72 - 5.24[/tex]

[tex]h = 10.48[/tex]

Hence, the dimension that maximize the volume is:

[tex]r = 5.24[/tex] --- Radius

[tex]h = 10.48[/tex] --- Height

We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.