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Surface Area of a can is 517.8 cm^2. Maximize the volume of this can using the measured surface area.

Sagot :

Answer:

[tex]r = 5.24[/tex] --- Radius

[tex]h = 10.48[/tex] --- Height

Explanation:

Given

Object: Can (Cylinder)

[tex]Surface\ Area = 517.8cm^2[/tex]

Required

Maximize the volume

The surface area is:

[tex]S.A = 2\pi r^2 + 2\pi rh[/tex]

Substitute 517.8 for S.A

[tex]517.8 = 2\pi r^2 + 2\pi rh[/tex]

Divide through by 2

[tex]258.9 = \pi r^2 + \pi rh[/tex]

Factorize:

[tex]258.9 = \pi r(r + h)[/tex]

Divide through by [tex]\pi r[/tex]

[tex]\frac{258.9}{\pi r} = r + h[/tex]

Make h the subject

[tex]h = \frac{258.9}{\pi r} - r[/tex] --- (1)

Volume (V) is calculated as:

[tex]V = \pi r^2h[/tex]

Substitute (1) for h

[tex]V = \pi r^2(\frac{258.9}{\pi r} - r)[/tex]

Open Bracket

[tex]V = 258.9r - \pi r^3[/tex]

Differentiate V

[tex]V' = 258.9 - 3\pi r^2[/tex]

Set V' to 0

[tex]0 = 258.9 - 3\pi r^2[/tex]

Collect Like Terms

[tex]3\pi r^2 = 258.9[/tex]

Divide through by 3

[tex]\pi r^2 = 86.3[/tex]

Divide through by [tex]\pi[/tex]

[tex]r^2 = \frac{86.3}{\pi}[/tex]

[tex]r^2 = \frac{86.3*7}{22}[/tex]

[tex]r^2 = \frac{604.1}{22}[/tex]

Take square root of both sides

[tex]r = \sqrt{\frac{604.1}{22}[/tex]

[tex]r = 5.24[/tex]

Recall that:

[tex]h = \frac{258.9}{\pi r} - r[/tex]

Substitute 5.24 for r

[tex]h = \frac{258.9}{\pi * 5.24} - 5.24[/tex]

[tex]h = \frac{258.9*7}{22 * 5.24} - 5.24[/tex]

[tex]h = \frac{1812.3}{115.28} - 5.24[/tex]

[tex]h = 15.72 - 5.24[/tex]

[tex]h = 10.48[/tex]

Hence, the dimension that maximize the volume is:

[tex]r = 5.24[/tex] --- Radius

[tex]h = 10.48[/tex] --- Height