Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Find the volume of the cone.


Find The Volume Of The Cone class=

Sagot :

Answer:

Step-by-step explanation:

volume=1/3 πr²h

=1/3×π×3²×4

=12π ft³

≈37.70 ft³

Answer :

  • 37.7 cm³ is the volume of the cone.

Explaination :

Here we have to calculate the volume of the cone which is provided in the figure.

As we know that volume of cone is calculated by the formula :

  • [tex]\orange{\boxed{\bf{V \: = \: \frac{1}{3} \: \pi \:r {}^{2}h }}} [/tex]

Here,

  • r is radius
  • h is height
  • Value of π is 22/7

We have :

  • Radius (r) is 3 ft.
  • Height (h) is 4 ft.

Putting the values in the formula :

[tex]\longrightarrow \: \sf{V \: = \: \dfrac{1}{3} \: \pi \:r {}^{2}h } \\ \\ \longrightarrow \: \sf{V \: = \: \dfrac{1}{3} \: \times \dfrac{22}{7} \:(3) {}^{2}(4) } \\ \\ \longrightarrow \: \sf{V \: = \: \dfrac{1}{3} \: \times \dfrac{22}{7} \:(3 \times 3)(4) } \\ \\ \longrightarrow \: \sf{V \: = \: \dfrac{1}{3} \: \times \dfrac{22}{7} \:(9)(4) } \\ \\ \longrightarrow \: \sf{V \: = \: \dfrac{1}{3} \: \times \dfrac{22}{7} \: \times 9(4) } \\ \\ \longrightarrow \: \sf{V \: = \: \dfrac{1}{3} \: \times \dfrac{22}{7} \: \times 9 \times 4 } \\ \\ \longrightarrow \: \sf{V \: = \: \dfrac{1}{ \cancel3} \: \times \dfrac{22}{7} \: \times \cancel9 \times 4 } \\ \\ \longrightarrow \: \sf{V \: = \: \dfrac{1}{1} \: \times \dfrac{22}{7} \: \times 3 \times 4 } \\ \\ \longrightarrow \: \sf{V \: = \: \dfrac{22}{7} \: \times 3 \times 4 } \\ \\ \longrightarrow \: \sf{V \: = \: \dfrac{22 \times 3 \times 4}{7} } \\ \\ \longrightarrow \: \sf{V \: = \: \dfrac{66 \times 4}{7} } \\ \\ \longrightarrow \: \sf{V \: = \: \dfrac{264}{7} } \\ \\ \longrightarrow \: \sf{V \: = \: \cancel\dfrac{264}{7} } \\ \\ \longrightarrow \: \underline{\underline{\red{\bf{V \: = \: 37.7 }}}}[/tex]