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A cannonball is launched off a 100 m cliff horizontally with an initial velocity of 50

m/s. The goal is to hit a target 200m away but the cannonball goes too far. Which of

these changes could make the cannonball travel a shorter distance?

a) Decrease the launch speed of the cannon.

UbNeither of these will decrease the range of the cannonball

d Both of these will decrease the range of the cannonball

Lower the launch height of the cannon.


Sagot :

Answer:

the correct one is b,  Decrease the launch speed and Low the launch height

Explanation:

Let's find the solution to the problem in order to answer the questions.

The bullet is fired horizontally with a velocity vo, let's find the time or it takes to reach the ground

      y = y₀ + [tex]v_{oy}[/tex] t - ½ g t²

as it shoots horizontally v_{oy} = 0 and when I reach the floor y = 0

       0 = y₀ - ½ g t2

       t = [tex]\sqrt{\frac{2y_{o} }{g} }[/tex]

where y₀ is the height of the cliff

at this time the bullet recreates a distance of

       x = v₀ t

we substitute

       x = v₀ \sqrt{\frac{2y_{o} }{g} }

There, to reduce the range of the bullet, we must decrease its speed. This is the magnitude that most affects the distance and to a lesser degree we can decrease the height.

When checking the answers, the correct one is b

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