Answered

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Find two consecutive numbers whose sum is 117

Sagot :

[tex]n+n+1=117\\ 2n=116\\ n=58\\ n+1=59[/tex]

These numbers are 58 and 59.
So,

x + y = 117
y = x + 1
x + x + 1 = 117

Collect Like Terms
2x + 1 = 117

Subtract 1 from both sides
2x = 116

Divide both sides by 2
x = 58

y = x + 1

y = 58 + 1

y = 59

The 2 consecutive integers are 58 and 59.