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Find the slope of the line:
5x+3y=6


Sagot :

To get the result we have to transform given formula into y=ax+b form.
Lets do this
5x+3y=6   /-5x  (subtract 5x both sides)
3y=-5x+6  /:3  (divide both sides by 3)
y=[tex] -\frac{5}{3} x+6[/tex]
In form y=ax+b we know that a is slope and b is y intersect. We can read from our transformed equation that slope a=[tex] -\frac{5}{3} [/tex]and its the result

[tex]5x+3y=6\\ 3y=-5x+6\\ y=-\frac{5}{3}x+2\\ \boxed{m=-\frac{5}{3}}[/tex]