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Sagot :
There's an infinite number of possible answers because there might be any multiplication of 3 for boys and any multiplication of 2 for girls. So, for example:
There might be 3 boys and 2 girls.
There might be 6 boys and 4 girls.
There might be 9 boys and 6 girls.
There might be 12 boys and 8 girls.
etc...
In each case the ratio stays the same - 3 : 2.
Of course there probably can't be more than a few dozens of people in one class, but theoretically we can raise the numbers up to infinite.
There might be 3 boys and 2 girls.
There might be 6 boys and 4 girls.
There might be 9 boys and 6 girls.
There might be 12 boys and 8 girls.
etc...
In each case the ratio stays the same - 3 : 2.
Of course there probably can't be more than a few dozens of people in one class, but theoretically we can raise the numbers up to infinite.
Answer:
There could be 6 boys and 4 girls
There are several possible answers.
Step-by-step explanation:
Consider the provided ratio.
the ratio of boys to girls is equal to 3:2, it means that for every 2 girls in the class there will be 3 boys.
Let us assume there are 6 boys in the class.
Then the number of girls would be 4 because the ratio still have to be 3 to 2.
[tex]\frac{6}{4}= \frac{3}{2}[/tex]
We can use algebra to figure this out or you can use logic.
The boys to girls ratio is 3:2, This can be written as:
[tex]\frac{boys}{girls} =\frac{3}{2}[/tex]
If we multiply numerator and denominator by 2 we get.
[tex]\frac{boys}{girls} =\frac{3\times 2}{2\times 2}=\frac{6}{4}[/tex]
That means for every 6 boys there are 4 girls, either way the ratio remains the same.
Similarly If we multiply numerator and denominator by 3 we get.
[tex]\frac{boys}{girls} =\frac{3\times 3}{2\times 3}=\frac{9}{6}[/tex]
That means for every 9 boys there are 6 girls, and the ratio remains the same.
So there are more than one possible answer.
Hence, there are several possible answers.
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