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La ce distanta de la suprafata Pamintului intensitatea cimpului sau gravidational este egala cu 1 N/kg ?
Va rooogggg .. ofer 21 puncte !!!

Sagot :

AL2006
Acceleration of gravity is proportional to  1/D² .
('D' is the distance from the Earth's center.)

We need  (D / R)² = 9.8
('R' is the Earth's radius.)

D/R = √9.8 = 3.13

Distance from Earth's center = 3.13 R
Distance above Earth's surface = 2.13 R = about 13,570 km =====================================================

Accelerarea de gravitate este proporțională cu 1 / D².
('D este distanța de centrul Pământului.)

Avem nevoie de (D / R) ² = 9,8
('R' este raza Pământului.)

D / R = √9.8 = 3,13

Distanța de la centrul Pamantului = 3,13 R
Distanța de deasupra suprafetei Pamantului = 2.13 R = aproximativ 13,570 km
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