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6x-5y=22 y=-8 using systems of equations by substitution

Sagot :

AndyBryer
We need to sub y=-8 into the first equation
6x+40=22
6x=-18
x=-3
luana
[tex] \left \{ {{6x-5y=22} \atop {y=-8}} \right. \\\\ substitute\ y=-8\ into\ first\ equation\\\\ 6x-5*(-8)=22\\\\ 6x+40=22\ \ \ | subtract\ 40\\\\ 6x=-18\ \ \ | divide\ by\ 6\\\\ x=-3\\\\ y=-8[/tex]
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