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A number cube is rolled three times. An outcome is represented by a string of the sort OEE (meaning an odd number on the first roll, an even number on the
second roll, and an even number on the third roll). The 8 outcomes are listed in the table below. Note that each outcome has the same probability,
For each of the three events in the table, check the outcomes) that are contained in the event. Then, in the last column, enter the probability of the event

Sagot :

Answer:

Event A: Exactly 1 odd number: EOE, EEO, OEE 3/8 Probability

Event B: More even numbers than odd numbers: EOE, EEO, OEE,EEE 1/2 Probability

Event C: Alternating even number and odd number (with either coming first): EOE, OEO 1/4 Probability

Step-by-step explanation:

Cricetus

The probability of the given events is:

  • [tex]\frac{1}{4}[/tex]
  • [tex]\frac{1}{4}[/tex]
  • [tex]\frac{3}{8}[/tex]

According to the question,

Number of outcomes = 8

Event A:

Having the alternative even and odd numbers.

→ [tex](EOE, OEO) = \frac{2}{8}[/tex]

                         [tex]= \frac{1}{4}[/tex]

Event B:

No even number and last two rolls.

→ [tex](EOO,OOO) = \frac{2}{8}[/tex]

                         [tex]= \frac{1}{4}[/tex]

Event C:

Exactly on odd number:

→ [tex](EOE,OEE,EEO) = \frac{3}{8}[/tex]

Thus the above approach is correct.

Learn more about probability here:

https://brainly.com/question/11234923

View image Cricetus
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