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The length of a rectangle is 9 yd more than twice the width x. The area is 455 yd?.
Write an equation in terms of x that represents the given relationship.


Sagot :

deand34

Answer:

x * (2x + 9) = 455

Step-by-step explanation:

To express the width in terms of x, given information

x = width

The given information says the length is 9 more than 2 times the width. Length can be expressed in terms of x like this.

2x + 9 = length

The area of a rectangle is length x width, and the given area is 455.

x * (2x + 9) = 455 or 2x^2 + 9x = 455

The equation in terms of x of the area of the rectangle should be [tex]2x^2 + 9x = 455[/tex]

Given that

  • The length of the rectangle is 9 yards i.e. more than twice the width. i.e.. 2x + 9.
  • And, the width is x.
  • The area is 455 yards.

The area of the rectangle is

= [tex]length \times breadth[/tex]

[tex](2x + 9( (x) =455 \\\\ 2x^2 + 9x = 455[/tex]

Therefore we can conclude that The equation in terms of x of the area of the rectangle should be [tex]2x^2 + 9x = 455[/tex]

Learn more about the rectangle here: brainly.com/question/16167300

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