Answered

Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Get immediate and reliable answers to your questions from a community of experienced experts on our platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

A ball rolls with a speed of 3 m/s across a level table that is 1.5m above the floor. How far along the floor is the landing spot from the table?

Sagot :

Answer:

d = 1.65 m

Explanation:

Given that,

The speed of a ball, v = 3 m/s

A ball rolls a level table that is 1.5 m above the floor.

We can find how long the ball is in free fall. We can use the second equation of kinematics as follows :

[tex]s=ut+\dfrac{1}{2}gt^2[/tex]

u is the initial speed in the vertical direction

So,

[tex]s=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2s}{g}} \\\\t=\sqrt{\dfrac{2\times 1.5}{9.8}} \\\\t=0.55\ s[/tex]

Now, using the formula of velocity.

[tex]v=\dfrac{d}{t}\\\\d=vt\\\\d=3\times 0.55\\\\d=1.65\ m[/tex]

So, the landing spot is at 1.65 m from the table.

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.