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Moles|Grams|Liters

1.2 mol N2=__ L

3 mol H2=__ L

0.5 mol CO2=__ L

10.3 L NO2=__ moles

67.2 L SO2=__ moles

89.6 L NO=__ moles

44.8 L NO2=__ grams

201.6 L H2=__ grams

65 grams CO=__ L

152 grams F2=__ L​

Sagot :

mickymike92

Answer:

1.2 mol N2 = 26.88 L

3 mol H2 =  67.2 L

0.5 mol CO2 = 11.2 L

10.3 L NO2 = 0.46 moles

67.2 L SO2 = 67.2 / 22.4 = 3 moles

89.6 L NO = 89.6 /22.4 = 4 moles

44.8 L NO2  = 92 grams

201.6 L H2 = 18 g

65 grams CO = 51.9 L

152 grams F2  = 89.6 L

Explanation:

1 mole of a gas occupies a volume of 22.4 L

(N = 14, O = 16, C = 12, H = 1, F = 19)

1.2 mol N2= 1.2 * 22.4 L = 26.88 L

3 mol H2 = 3 * 22.4 L = 67.2 L

0.5 mol CO2 = 0.5 * 22.4  L = 11.2 L

10.3 L NO2 =  10.3 / 22.4 L = 0.46 moles

67.2 L SO2 = 67.2 / 22.4 = 3 moles

89.6 L NO = 89.6 /22.4 = 4 moles

1 mole or 22.4 L of NO₂ has a mass of 46 g

44.8 L NO2 = (44.8 /22.4) * 46 grams = 92 grams

1 mole or 22.4 L of H₂ has a mass of 2 g

201.6 L H2 = (201.6 / 22.4) * 2 grams = 18 g

1 mole or 22.4 L of CO has a mass of 28 g

65 grams CO = 65/28 * 22.4 L = 51.9 L

1 mole of F₂ has a mass of 38 grams

152 grams F2 = 152/38 * 22.4 L = 89.6 L

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