You have a choice of two different Internet Service companies: AOL and Yahoo. One of AOL’s plans charges $19.99
for a month and a charge of $2.00 per hour. Yahoo’s similar plan offers service for only $14.99 a month and a charge
of $2.50 per hour. How many hours would you need to use the internet for the charges to be equal? What would the
monthly charge be?

Question

01-02-2021
Mathematics

Answered

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You have a choice of two different Internet Service companies: AOL and Yahoo. One of AOL’s plans charges $19.99
for a month and a charge of $2.00 per hour. Yahoo’s similar plan offers service for only $14.99 a month and a charge
of $2.50 per hour. How many hours would you need to use the internet for the charges to be equal? What would the
monthly charge be?

Sagot :

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adrianac37 adrianac37 · Answer 1 · 2021-02-01T03:41:48-05:00

First, you’re starting equation should look something like this:
19.99+2h= 14.99+2.50h
H equaling hours
You would then subtract 2h from 2.50h, so now you’re equation will look like this:
19.99=14.99+0.50h
Then, subtract 14.99 from 19.99. The equation should look like:
5=0.50h
Finally, divided 0.50h to 5 to get 10
10=h
You’re finally answer should be, It would take 10 hours for the Internet cost to be equal. The monthly charge would then be 39.99. You can find your answer by replacing h on either sides or your starting equation and insert 10.
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If you have any further questions, feel free to ask!

Sagot :

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