Given:
The equation of a function is
[tex]y=(x-4)^2+1[/tex]
To find:
The graph of the given function.
Solution:
The vertex form of a parabola is
[tex]y=(x-h)^2+k[/tex] ...(i)
Where, (h,k) is vertex of the parabola.
We have,
[tex]y=(x-4)^2+1[/tex] ...(ii)
From (i) and (ii), we get
[tex]h=4, k=1[/tex]
The vertex of the parabola is (4,1).
Now, the table of values is
x y
2 5
3 2
4 1
5 2
6 5
Plot these points on a coordinate plane and connect them by a free hand curve.
The graph of given function is shown below.
