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Sagot :
Answer:
[tex] {7}^{2} \times \sqrt[3]{7}\\ = {7}^{2} \times {7}^{ \frac{1}{3} } \\ = {7}^{(2 + \frac{1}{3}) } \\ = {7}^{ \frac{(6 + 1)}{3}} \\ = \boxed{{7}^{ \frac{7}{3}}}✓[/tex]
7⁷/³ is the right answer.
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