Answered

Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Get immediate and reliable solutions to your questions from a knowledgeable community of professionals on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

A sample of cobalt-60 has an activity of 2000 Bq. What will the activity be after 10 years? Cobalt-60 has a half life of 5 years.

Sagot :

pstnonsonjoku

Answer:

500.3 Bq

Explanation:

From the formula;

0.693/t1/2 = 2.303/t log (Ao/A)

Where;

t1/12 = half life = 5 years

Ao = initial activity = 2000 Bq

0.693/5 = 2.303/10 log (2000/A)

0.1386= 0.2303  log (2000/A)

0.1386/0.2303 =  log (2000/A)

0.6018 = log (2000/A)

(2000/A) = Antilog (0.6018)

(2000/A) = 3.9976

A = 2000/3.9976

A = 500.3 Bq

Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.