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A vacuum cleaner has a rating of 460 W on 230 V mains. The value of the fuse connected in the plug will be

Sagot :

Answer:

2 amps

Explanation:

Given data

Power = 460W

voltage= 230V

Required

The amperage/ current of the fuse

Recall  P= IV

I= P/V

I= 460/230

I=2 amps

Hence the current of the fuse is 2 amps