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What is the equation of the line with a y-intercept of 4 and a point (8,8)? ​

Sagot :

CintiaSalazar

Answer:

The equation of the line with a y-intercept of 4 and a point (8,8) is [tex]y=\frac{1}{2} *x+4[/tex]

Step-by-step explanation:

A linear equation can be expressed in the form

y = m * x + b

where x and y are coordinates of a point, m is the slope and b is the y-intercept. Since this equation describes a line in terms of its slope and its y-intercept, this equation is said to be in its slope-intercept form.

Graphically this equation represents a line.

In this case, you know:

  • The point (x,y)=(8,8)
  • Y-intercept= 4

Replacing:

8=m*8 +4

Solving:

8-4=m*8

4=m*8

4÷8= m

[tex]m=\frac{1}{2}[/tex]

Then, the equation of the line with a y-intercept of 4 and a point (8,8) is [tex]y=\frac{1}{2} *x+4[/tex]

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