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The specific heat capacity of iron is 450.5. A 15.5 kg block of iron with

an initial temperature of 20 degrees Celsius is heated with 250 J. What will

the final temperature of the iron be?


Sagot :

Answer:

[tex]T_f=20.03^{\circ} C[/tex]

Explanation:

Given that,

The specific heat capacity of iron is 450.5 J/g°C

The mass of block of iron, m = 15.5 kg

Initial temperature, [tex]T_i=20^{\circ} C[/tex]

Heat required, Q = 250 J

We need to find the final temperature of the iron. The formula for heat required is given by :

[tex]Q=mc\Delta T\\\\Q=mc(T_f-T_i)\\\\\dfrac{Q}{mc}=(T_f-T_i)\\\\T_f=\dfrac{Q}{mc}+T_i\\\\T_f=\dfrac{250}{15.5(450.5)}+20\\\\T_f=20.03^{\circ} C[/tex]

So, the final temperature of the iron is [tex]20.03^{\circ} C[/tex].