Answered

Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Find reliable answers to your questions from a wide community of knowledgeable experts on our user-friendly Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

The contractor for a new school put a rectangular garden in the courtyard. The length of this garden is 5 feet longer than its width. If this area is 414 square feet, what is the length of the rectangle?

Sagot :

abidemiokin

Answer:

23ft

Step-by-step explanation:

Area of the rectangle = LW

L is the length

W is the width

Given

Area = 414ft²

If the length of this garden is 5 feet longer than its width, then;

L = W+5

Substitute into the formula

414 = (W+5)W

414 = W²+5W

W²+5W-414 = 0

W = -5±√5²-4(-414)/2

W = -5±√25+1656/2

W = -5±√1681/2

W = -5+41/2

W = 36/2

W = 18ft

Since L = W+5

L = 18+5

L = 23ft

Hence the length of the rectangle is 23ft

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.