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Sagot :
Answer:
(log64x³) / 2 log = a
Step-by-step explanation:
Given the equation :
log4x 2^a = 3
Recall: If :
loga b = c becomes ; a^c = b
log4x 2^a = 3 ; becomes ; (4x)^3 = 2^a
4^3 * x^3 = 2^a
64x^3 = 2a
log64x³ = log 2a
log64x³ = 2 log a
Divide both sides by 2 log
(log64x³) / 2 log = 2 log a / 2 log
(log64x³) / 2 log = a
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