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Sagot :
Answer:
Equation of the straight line passing through the point ( 4,2) and (7,-3) is
5 x + 4y - 28=0
Step-by-step explanation:
Step(i):-
Given points are ( 4,2 0 and ( 7,-3)
Slope of the line
[tex]m = \frac{y_{2}-y_{1} }{x_{2} -x_{1} } = \frac{-3-2}{7-4} = \frac{-5}{4}[/tex]
Step(ii):-
Equation of the straight line passing through the point ( 4,2) and
having slope m = [tex]\frac{-5}{4}[/tex]
y - y₁ = m( x- x₁ )
[tex]y - 2 = \frac{-5}{4} ( x-4)[/tex]
4( y -2) = -5( x-4)
4 y - 8 = - 5x +20
5x +4y -8 -20=0
5 x + 4y - 28=0
Final answer:-
Equation of the straight line passing through the point ( 4,2) and (7,-3) is
5 x + 4y - 28=0
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