Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Get detailed answers to your questions from a community of experts dedicated to providing accurate information. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
Answer:
Equation of the straight line passing through the point ( 4,2) and (7,-3) is
5 x + 4y - 28=0
Step-by-step explanation:
Step(i):-
Given points are ( 4,2 0 and ( 7,-3)
Slope of the line
[tex]m = \frac{y_{2}-y_{1} }{x_{2} -x_{1} } = \frac{-3-2}{7-4} = \frac{-5}{4}[/tex]
Step(ii):-
Equation of the straight line passing through the point ( 4,2) and
having slope m = [tex]\frac{-5}{4}[/tex]
y - y₁ = m( x- x₁ )
[tex]y - 2 = \frac{-5}{4} ( x-4)[/tex]
4( y -2) = -5( x-4)
4 y - 8 = - 5x +20
5x +4y -8 -20=0
5 x + 4y - 28=0
Final answer:-
Equation of the straight line passing through the point ( 4,2) and (7,-3) is
5 x + 4y - 28=0
We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.
