Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Its PreCal I’ll give brainliest

Its PreCal Ill Give Brainliest class=

Sagot :

Answer:

tan²x + tan x - 12 = 0 (1)

suppose: tan x = t

(1)=> t² + t - 12 = 0

a = 1    b = 1     c = -12

⇒ Δ = b² - 4ac = 1 + 48 = 49 > 0 => has 2 solutions

=> t = [tex]\frac{1+\sqrt{49} }{2}=\frac{8}{2}=4[/tex]

or t = [tex]\frac{1-\sqrt{49} }{2}=\frac{-6}{2}= -3[/tex]

because t = tan x => tan x = 4 or tan x = -3

because x ∈ [0;2pi) => with tan x = 4 => x = arctan(4)  or x = arctan(4) + pi

                                     with tan x = -3 => x = arctan(-3) + pi

Step-by-step explanation: