Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
Answer:
s e([tex]p^{-} _{1} - p^{-} _{2}[/tex] ) = 0.07576
Step-by-step explanation:
Step(i):-
The proportion of the first sample
[tex]p^{-} _{1} = \frac{x_{1} }{n_{1} } = \frac{23}{53} = 0.43396[/tex]
The proportion of the second sample
[tex]p^{-} _{2} = \frac{x_{2} }{n_{2} } = \frac{48}{178} = 0.2696[/tex]
Step(ii):-
Standard Error of ([tex]p^{-} _{1} - p^{-} _{2}[/tex]) is determined by
[tex]se(p^{-} _{1} - p^{-} _{2}) = \sqrt{\frac{p^{-} _{1} (1-p^{-} _{1} )}{n_{1} }+\frac{p^{-} _{2}(1-p^{-} _{2} ) }{n_{2} } }[/tex]
[tex]se(p^{-} _{1} - p^{-} _{2}) = \sqrt{\frac{0.43396) (1-0.43396 )}{53 }+\frac{0.2696(1-0.2696 ) }{178} }[/tex]
on simplification, we get
s e([tex]p^{-} _{1} - p^{-} _{2}[/tex] ) = 0.07576
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.
