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Sagot :
Answer:
2.29m
Explanation:
Given parameters:
Mass of the coconut = 1.4kg
Final velocity = 6.7m/s
Initial velocity = 0m/s
Unknown:
Height of the coconut initially = ?
Solution:
To solve this problem, we use one of the kinematics equation. The one given below is the best one to use.
V² = U² + 2gH
V is the final velocity
U is the initial velocity
g is the acceleration due to gravity
H is the height
So;
6.7² = 0² + (2 x 9.8 x h)
44.89 = 19.6h
h = 2.29m
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