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If line q has a slope of -3/8, what is the slope of any line perpendicular to to q?

Sagot :

Answer:

The slope of line perpendicular to line q is 8/3.

Step-by-step explanation:

Given that:

Slope of a line q is -3/8

Slope is the steepness of any line.

Let,

x be the slope of line perpendicular to line q.

The product of slopes of two perpendicular lines is equal to -1.

[tex]\frac{-3}{8}x = -1[/tex]

Multiplying both sides -8/3

[tex]\frac{-8}{3}*\frac{-3}{8}x=-1*\frac{-8}{3}[/tex]

x = 8/3

Hence,

The slope of line perpendicular to line q is 8/3.