Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Explore in-depth answers to your questions from a knowledgeable community of experts across different fields. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
Answer:e. The sampling distribution of the difference in sample proportion is approximately normal.
Step-by-step explanation:
(200) (0.06) >= 10
(200) (0.94) >=10
(197)(0.086) >=10
(197)(0.914) >= 10
We test the sample proportions of it is normal :
Deer population 1:
Sample size, n1 = 200
Proportion, p1 = 0.06
q = 1 - p = 1 - 0.06 = 0.94
n1 * p = 200 * 0.06 = 12
n1 * q = 200 * 0.94 = 188
Deer population 2:
Sample size, n2 = 197
Proportion, p = 0.086
q = 1 - p = 1 - 0.086 = 0.914
n2 * p = 197 * 0.086 = 16.94
n2 * q = 197 * 0.914 = 180.06
Since for samples and proportions ;
n*p and nq ≥ 10 ;
We cm conclude that the sampling distribution of the difference in sample mean is appropriately normal.
The sampling distribution of the difference in sample proportions is approximately normal because samples and proportions are greater than or equal to 10.
Given :
- A wildlife biologist is doing research on chronic wasting disease and its impact on the deer populations in northern Colorado.
- A random sample of 200 deer was obtained from one region and a random sample of 197 deer was obtained from the other region.
For dear population 1, the sample size is 200 and proportion is 0.06.
[tex]\rm q_1 = 1-p_1=1-0.06=0.94[/tex]
[tex]\rm n_1p_1=200\times 0.06=12\\[/tex]
[tex]\rm n_1q_1=200\times 0.94 = 188[/tex]
Now, for dear population 2, the sample size is 197 and the proportion is 0.086.
[tex]\rm q_2 = 1-p_2=1-0.086=0.914[/tex]
[tex]\rm n_2p_2=197\times 0.086=16.94[/tex]
[tex]\rm n_2q_2=197\times 0.914 = 180.06[/tex]
Therefore, from the above calculations, it can be concluded that the sampling distribution of the difference in sample proportions is approximately normal because samples and proportions are greater than or equal to 10.
So, the correct option is e).
For more information, refer to the link given below:
https://brainly.com/question/795909
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.