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Can I get some help on this math problem

Can I Get Some Help On This Math Problem class=

Sagot :

Answer:

[tex]x=3\sqrt{5}[/tex]

Step-by-step explanation:

Right Triangles

Right triangles have one of its interior angles with a measure of 90°.

In right triangles the Pythagora's Theorem is satisfied.

Being c the longest side (hypotenuse), a and b the shorter sides (the legs), then:

[tex]c^2=a^2+b^2[/tex]

We have modified the image to include some known data. Both triangles are congruent since they share one side, have a right angle, and have the same base length.

This means the value of x can be calculated as the hypotenuse of the triangle 3-6-x:

[tex]x^2=3^2+6^2=9+36=45[/tex]

[tex]x=\sqrt{45}=\sqrt{9*5}[/tex]

[tex]\boxed{x=3\sqrt{5}}[/tex]