Answered

At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Get detailed answers to your questions from a community of experts dedicated to providing accurate information. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

A boat is cruising in a straight line at a constant speed of 2.5 m/s when it is shifted into neutral. After coasting 14 mm the engine is engaged again, and the boat resumes cruising at the reduced constant speed of 1.5 m/s. Assuming constant acceleration while coasting,

a. How much time did it take for the boat to coast the 12 m?
b. What was the boat’s acceleration while it was coasting?
c. What was the speed of the boat when it had coasted for 6.0 m? Explain.

Sagot :

Answer:

Explanation:

a ) distance s = 12 m .

constant speed = 1.5 m/s

time taken to coast 12 m

= distance / speed

= 12 / 1.5 = 8 s

b ) initial velocity u = 2.5 m /s

final velocity v = 1.5 m /s

displacement s = 14 m

acceleration a = ?

v² = u² + 2 as

1.5² = 2.5² + 2 a x 14

a = - .1428 m /s²

= - 14.28 cm / s²

c )

v = ?

u = 2.5 m /s

s = 6 m

a = -   .1428 m /s²

v² = u² - 2 as

= 2.5² - 2 x 6 x .1428

= 6.25 - 1.71

= 4.54

v = 2.13 m /s .

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.