Answered

Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

A gas is enclosed in a cylinder fitted with a light frictionless piston and maintained at atmospheric pressure. When 1400 kcal of heat is added to the gas, the volume is observed to increase slowly from 12.0 m3 to 19.9 m3.
a) Calculate the work done by the gas.
I found this to be 7.4 * 10^5 J
b) Calculate the change in internal energy of the gas
____ J

Sagot :

onyebuchinnaji

Answer:

(a) The work done by the gas 8.005 x 10⁵ J

(b) the change in internal energy is 5.0575 x 10⁶ J

Explanation:

Given;

heat added to the gas, Q = 1400 kcal = 1400 kcal x 4184 J/kcal = 5.858 x 10⁶ J.

change in volume, ΔV = 19.9 m³ - 12.0 m³ = 7.9 m³

atmospheric pressure, P = 101325 N/m²

(a) The work done by the gas = PΔV

                                            = 101325 x 7.9

                                            = 8.005 x 10⁵ J

(b) the change in internal energy is obtained from first law of thermodynamic;

ΔU = Q - W

ΔU = 5.858 x 10⁶ J - 8.005 x 10⁵ J

ΔU = 58.58 x 10⁵J - 8.005 x 10⁵ J

ΔU = 5.0575 x 10⁶ J

Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.