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A team of ten cyclists wants to choose leaders. in how many ways can the team choose one captain and then two assistants?
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Sagot :

Answer:

720

Step-by-step explanation:

10 times 9 times 8 equals 720

720 ways can the team choose one captain and then two assistants.

We need to find how many ways can the team choose one captain and then two assistants.

What is the formula to find the permutation?

The formula to find the permutation is [tex]nP_{r} =\frac{n!}{(n-r)!}[/tex].

Now, [tex]10P_{3} =\frac{10!}{(10-3)!}[/tex]

=10×9×8×7!/7!=720

Therefore, one captain and then two assistants can be chosen in 720 ways.

To learn more about the permutation visit:

https://brainly.com/question/1216161.

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