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A superball rebounds half the height it drops. A student drops the superball from the top of a building, 176 feet above the ground. How far
above the ground is the ball when it has traveled a distance of 500 feet?

Sagot :

Answer:

62.48 ft.

Step-by-step explanation:

Initial height: 50 ft.

First rebound: 10 ft.

Second rebound: 2 ft.

Third rebound: 0.4 ft.

Fourth rebound: 0.08 ft.

If we approximate the fourth rebound to zero, we'll have:

50 + 10 + 2 + 0.4 + 0.08 = 62.48 ft.

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