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Please help due ASAP
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Please Help Due ASAP Hxhdbdidhdbbr class=

Sagot :

Mid point M of CF will have coordinates,
x
M
=
x
C
+
x
F
2
=
3
+
9
2
=
6

y
M
=
y
C
+
y
F
2
=
4
+
8
2
=
6

Using distance formula,
Distance
¯¯¯¯¯¯¯
M
F
=

(
x
M

x
F
)
2
+
(
y
M

y
F
)
2

=

(
6

9
)
2
+
(
6

8
)
2
=

13

3.6056
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