Answered

Looking for answers? Westonci.ca is your go-to Q&A platform, offering quick, trustworthy responses from a community of experts. Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Water flows through a first pipe of diameter 3 inches. If it is desired to use another pipe for the same flow rate such that the velocity head in the second pipe is twice the velocity head in the first pipe, determine the diameter of the second pipe.

Sagot :

nuhulawal20

Answer:

the diameter of the second pipe is 2.52 in

Explanation:  

Given the data in the question;

We know that; the rate of flow is the same;

so

Av1 = Av2

v ∝ √h

[tex]\frac{A1}{A2}[/tex] = [tex]\frac{V2}{V1}[/tex]

[tex]\frac{A1}{A2}[/tex]  = √(  [tex]\frac{h2}{h1}[/tex] )

( π/4.D1² / π/4.D2² ) = √(  [tex]\frac{h2}{h1}[/tex] )

( D1² / D2² ) =  √(  [tex]\frac{2h1}{h1}[/tex] ) since second is double of first

so

( D1² / D2² ) =  √(  [tex]\frac{2}{1}[/tex] )  

3² / D2² =  √2

D2²√2  = 9

D2² = 9/√2

D2² = 9 / 1.4142

D2² = 6.364

D2 = √ 6.364

D2 = 2.52 in

Therefore, the diameter of the second pipe is 2.52 in

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.