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A tire contains 1.50 mol of air at a gauge pressure of 205 kPa. If the volume of the air in the tire is 0.0120 m3, what is its temperature

Sagot :

maacastrobr

Answer:

197.07 K

Explanation:

To solve this problem we can use the PV=nRT equation, where:

  • P = 205 kPa ⇒ 205 * 0.00986 = 2.02 atm
  • V = 0.0120 m³ ⇒ 0.0120 * 1000 = 12 L
  • n = 1.50 mol
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • T = ?

We input the data:

  • 2.02 atm * 12 L = 1.50 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * T

And solve for T:

  • T = 197.07 K
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